0.0169=d^2

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Solution for 0.0169=d^2 equation:



0.0169=d^2
We move all terms to the left:
0.0169-(d^2)=0
We add all the numbers together, and all the variables
-1d^2+0.0169=0
a = -1; b = 0; c = +0.0169;
Δ = b2-4ac
Δ = 02-4·(-1)·0.0169
Δ = 0.0676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.0676}}{2*-1}=\frac{0-\sqrt{0.0676}}{-2} =-\frac{\sqrt{}}{-2} $
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.0676}}{2*-1}=\frac{0+\sqrt{0.0676}}{-2} =\frac{\sqrt{}}{-2} $

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